Another+attempt+around+4-4-13

In this reaction PrimeSTAR Max was used up to a 50 uL total volume. 1 uL of 2 uM of each primer was used for a final conc. of 1*"uL"*2*"uM"/(50*"uL") = 0.04*"uM". 30 cycles were performed. Later I added 1 uL of 10 uM primer and added 5 uL primestar max premix as well as 5 uL H20 and performed 5 more cycles Another 1 uL of 10 uM primer was added and 5 uL primestar max premix as well as 5 uL H20 was added and 5 more cycles were performed. Final concentration of primer would have been ( 1*"uL"*2*"uM"+1*"uL"*10*"uM"+1*"uL"*10*"uM")/(50*"uL") = 0.44 uM

What if I had not done 2 rounds of 1 uL 10 uM addition? Then what would the primer concentration have been? (1*"uL"*2*"uM"+1*"uL"*10*"uM")/(50.0*"uL")=0.24 uM which would have been quite reasonable. ^What if I just added 0.5 uL of 10 uM primer? (1*"uL"*2*"uM"+0.5*"uL"*10*"uM")/(50.0*"uL") = 0.14*"uM" which is still reasonable ^What if I want to end with a final of 0.3 uM?

(1*"uL"*2*"uM"+y*10*"uM")/(60.0*"uL") = 0.3*"uM" -> y=1.6 uL