Quantification+of+bands+6-24-13d1006

top band mean intensity 44.2 middle band mean intensity 102.2 bottom band mean intensity 114.8

empty part of gel 148

top band of ladder mean intensity 23.8

Band values inverted top band mean intensity 148-44.2=103.8 middle band mean intensity 148-102.2=45.8 bottom band mean intensity 148-114.8=33.2

empty part of gel 148-148=0

top band of ladder mean intensity 148-23.8=124.2

10 kb band is 36 ng when 20 uL is loaded. I loaded 12 uL so there was 36*"ng"/20*"uL"*(12*"uL")=21.6*"ng"

Therefore my conversion factor from amount to intensity is 21.6*"ng"/(124.2*"i")

top band amount 103.8*"i"*21.6*"ng"/(124.2*"i")=18.1*"ng" so 18.1*"ng"/(10*"uL")=1.8*"ng"/"uL"

middle band amount 45.8*"i"*21.6*"ng"/(124.2*"i")=7.97*"ng" so 7.97*"ng"/(10*"uL")=0.8*"ng"/"uL"

bottom band amount 33.2*"i"*21.6*"ng"/(124.2*"i")=5.8*"ng" so 5.8*"ng"/(10*"uL")=0.6*"ng"/"uL"